# Definition for singly-linked list.
class ListNode(object):
def __init__(self, x):
self.val = x
self.next = None
class Solution(object):
# def addTwoNumbers(self, l1, l2):
# """
# :type l1: ListNode
# :type l2: ListNode
# :rtype: ListNode
# """
# last = 0
# head = prev = None
# while True:
# if l2 is None and l1 is None and last == 0:
# break
# val = last
# if l2 is not None:
# val += l2.val
# l2 = l2.next
# if l1 is not None:
# val += l1.val
# l1 = l1.next
# if val >= 10:
# val = val % 10
# last = 1
# else:
# last = 0
# current = ListNode(val)
# if prev is None:
# head = current
# else:
# prev.next = current
# prev = current
# return head
def addTwoNumbers(self, l1, l2):
carry = 0
# dummy head
head = curr = ListNode(0)
while l1 or l2:
val = carry
if l1:
val += l1.val
l1 = l1.next
if l2:
val += l2.val
l2 = l2.next
curr.next = ListNode(val % 10)
curr = curr.next
carry = int(val / 10)
if carry > 0:
curr.next = ListNode(carry)
return head.next
Download Add Two Numbers.pyLeetcode 002 Add Two Numbers problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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