# Definition for singly-linked list.
# class ListNode(object):
# def __init__(self, x):
# self.val = x
# self.next = None
# class Solution(object):
# def swapPairs(self, head):
# """
# :type head: ListNode
# :rtype: ListNode
# """
class Solution(object):
# def swapPairs(self, head):
# current = last = last2 = head
# while current is not None:
# nex = current.next
# if current == last.next:
# last.next = nex
# current.next = last
# if last == head:
# head = current
# else:
# last2.next = current
# last2 = last
# last = nex
# current = nex
# return head
def swapPairs(self, head):
dummyHead = ListNode(-1)
dummyHead.next = head
prev, p = dummyHead, head
while p != None and p.next != None:
q, r = p.next, p.next.next
prev.next = q
q.next = p
p.next = r
prev = p
p = r
return dummyHead.next
Download Swap Nodes in Pairs.pyLeetcode 024 Swap Nodes in Pairs problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
self.val = x
self.next = None
class Solution(object):
def swapPairs(self, head):
"""
:type head: ListNode
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