import pdb
class Solution(object):
# def longestValidParentheses(self, s):
# """
# :type s: str
# :rtype: int
# """
# ls = len(s)
# start = [0] * (ls + 1)
# all = [0] * (ls + 1)
# for i in reversed(range(ls - 1)):
# if s[i] == '(':
# if s[i + 1] == ')':
# start[i] = 2
# if start[i + 1] + i + 1 < ls and s[start[i + 1] + i + 1] == ')':
# start[i] = 2 + start[i + 1]
# if start[start[i] + i] > 0:
# start[i] += start[start[i] + i]
# all[i] = max(start[i], all[i + 1])
# return all[0]
def longestValidParentheses(self, s):
# https://leetcode.com/discuss/87988/my-easy-o-n-java-solution-with-explanation
ls = len(s)
stack = []
data = [0] * ls
for i in range(ls):
curr = s[i]
if curr == '(':
stack.append(i)
else:
if len(stack) > 0:
data[i] = 1
data[stack.pop(-1)] = 1
tep, res = 0, 0
for t in data:
if t == 1:
tep += 1
else:
res = max(tep, res)
tep = 0
return max(tep, res)
if __name__ == '__main__':
s = Solution()
# print s.longestValidParentheses(")(((((()())()()))()(()))(")
print s.longestValidParentheses(')()())')
Download Longest Valid Parentheses.pyLeetcode 032 Longest Valid Parentheses problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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