class Solution(object):
def getPermutation(self, n, k):
"""
:type n: int
:type k: int
:rtype: str
"""
# let permutations with first identical num be a block
# target in (k - 1) / (n - 1)! block
remain = range(1, n + 1)
if k <= 1:
return ''.join(str(t) for t in remain)
total = 1
for num in remain[:-1]:
total *= num
res = self.do_getPermutation(remain, total, n - 1, k - 1)
return ''.join(str(t) for t in res)
def do_getPermutation(self, remain, curr, n, k):
if n == 0 or k <= 0 or curr == 0:
return remain
# which block
step = k / curr
# remain k value
k %= curr
curr /= n
res = [remain[step]] + self.do_getPermutation(remain[:step] + remain[step + 1:], curr, n - 1, k)
return res
if __name__ == '__main__':
s = Solution()
print s.getPermutation(3, 2)
# print s.getPermutation(2, 2)
Download Permutation Sequence.pyLeetcode 060 Permutation Sequence problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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