class Solution(object):
# def uniquePathsWithObstacles(self, obstacleGrid):
# """
# :type obstacleGrid: List[List[int]]
# :rtype: int
# """
# m, n = len(obstacleGrid), len(obstacleGrid[0])
# dmap = [[0] * n for _ in range(m)]
# for i in range(m):
# if obstacleGrid[i][0] != 1:
# dmap[i][0] = 1
# else:
# break
# for j in range(n):
# if obstacleGrid[0][j] != 1:
# dmap[0][j] = 1
# else:
# break
# for i in range(1, m):
# for j in range(1, n):
# if obstacleGrid[i][j] == 1:
# continue
# l = u = 0
# if i - 1 >= 0:
# u = dmap[i - 1][j]
# if j - 1 >= 0:
# l = dmap[i][j - 1]
# dmap[i][j] = l + u
# return dmap[m - 1][n - 1]
def uniquePathsWithObstacles(self, obstacleGrid):
m, n = len(obstacleGrid), len(obstacleGrid[0])
if m == 0:
return 0
dmap = [[0] * (n + 1) for _ in range(m + 1)]
dmap[m - 1][n] = 1
for i in range(m - 1, -1, -1):
for j in range(n - 1, -1, -1):
if obstacleGrid[i][j] == 1:
dmap[i][j] = 0
else:
dmap[i][j] = dmap[i][j + 1] + dmap[i + 1][j]
return dmap[0][0]
Download Unique Paths II.pyLeetcode 063 Unique Paths II problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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