class Solution(object):
# def isNumber(self, s):
# """
# :type s: str
# :rtype: bool
# """
# # remove lead and tail space
# s = s.strip()
# try:
# float(s)
# return True
# except:
# if '.' in s or ' ' in s:
# return False
# temp = s.split('e')
# if len(temp) == 2:
# try:
# int(temp[0])
# int(temp[1])
# except:
# return False
# return True
# return False
def isNumber(self, s):
s = s.strip()
ls, pos = len(s), 0
if ls == 0:
return False
if s[pos] == '+' or s[pos] == '-':
pos += 1
isNumeric = False
while pos < ls and s[pos].isdigit():
pos += 1
isNumeric = True
if pos < ls and s[pos] == '.':
pos += 1
while pos < ls and s[pos].isdigit():
pos += 1
isNumeric = True
elif pos < ls and s[pos] == 'e' and isNumeric:
isNumeric = False
pos += 1
if pos < ls and (s[pos] == '+' or s[pos] == '-'):
pos += 1
while pos < ls and s[pos].isdigit():
pos += 1
isNumeric = True
print pos, ls, isNumeric
if pos == ls and isNumeric:
return True
return False
Download Valid Number.pyLeetcode 065 Valid Number problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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