class Solution(object):
# https://discuss.leetcode.com/topic/17639/20ms-detailed-explained-c-solutions-o-n-space/2
# def minDistance(self, word1, word2):
# """
# :type word1: str
# :type word2: str
# :rtype: int
# """
# ls_1, ls_2 = len(word1), len(word2)
# dp = [[0] * (ls_2 + 1) for _ in range(ls_1 + 1)]
# for i in range(1, ls_1 + 1):
# dp[i][0] = i
# for j in range(1, ls_2 + 1):
# dp[0][j] = j
# for i in range(1, ls_1 + 1):
# for j in range(1, ls_2 + 1):
# if word1[i - 1] == word2[j - 1]:
# dp[i][j] = dp[i - 1][j - 1]
# else:
# dp[i][j] = min(dp[i - 1][j - 1] + 1,
# dp[i][j - 1] + 1,
# dp[i - 1][j] + 1)
# return dp[ls_1][ls_2]
def minDistance(self, word1, word2):
ls_1, ls_2 = len(word1), len(word2)
dp = list(range(ls_1 + 1))
for j in range(1, ls_2 + 1):
pre = dp[0]
dp[0] = j
for i in range(1, ls_1 + 1):
temp = dp[i]
if word1[i - 1] == word2[j - 1]:
dp[i] = pre
else:
dp[i] = min(pre + 1, dp[i] + 1, dp[i - 1] + 1)
pre = temp
return dp[ls_1]
if __name__ == '__main__':
# begin
s = Solution()
print (s.minDistance("horse","ros"))
print (s.minDistance("intention","execution"))
Download Edit Distance.pyLeetcode 072 Edit Distance problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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