class Solution(object):
def merge(self, nums1, m, nums2, n):
"""
:type nums1: List[int]
:type m: int
:type nums2: List[int]
:type n: int
:rtype: void Do not return anything, modify nums1 in-place instead.
"""
p1, p2 = m - 1, n - 1
pos = m + n - 1
while p1 >= 0 and p2 >= 0:
if nums1[p1] >= nums2[p2]:
nums1[pos] = nums1[p1]
p1 -= 1
else:
nums1[pos] = nums2[p2]
p2 -= 1
pos -= 1
while p2 >= 0:
nums1[pos] = nums2[p2]
p2 -= 1
pos -= 1
# def merge(self, nums1, m, nums2, n):
# # using slicing
# i, j, k = m - 1, n - 1, m + n - 1
# while i >= 0 and j >= 0:
# if nums1[i] > nums2[j]:
# nums1[k] = nums1[i]
# i -= 1
# else:
# nums1[k] = nums2[j]
# j -= 1
# k -= 1
#
# if j >= 0:
# nums1[:k + 1] = nums2[:j + 1]
Download Merge Sorted Array.pyLeetcode 088 Merge Sorted Array problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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