```
'''
Given head which is a reference node to a singly-linked list.
The value of each node in the linked list is either 0 or 1.
The linked list holds the binary representation of a number.
Return the decimal value of the number in the linked list.
Example 1:
Input: head = [1,0,1]
Output: 5
Explanation: (101) in base 2 = (5) in base 10
Example 2:
Input: head = [0]
Output: 0
Example 3:
Input: head = [1]
Output: 1
Example 4:
Input: head = [1,0,0,1,0,0,1,1,1,0,0,0,0,0,0]
Output: 18880
Example 5:
Input: head = [0,0]
Output: 0
Constraints:
The Linked List is not empty.
Number of nodes will not exceed 30.
Each node's value is either 0 or 1.
'''
# Definition for singly-linked list.
# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None
class Solution:
def getDecimalValue(self, head: ListNode) -> int:
binary_numbers_list = []
binary_numbers_list.append(head.val)
while(head.next is not None):
head = head.next
binary_numbers_list.append(head.val)
answer = 0
power = 0
# from len(binary_numbers_list) - 1 -> 0
for digit in range(len(binary_numbers_list) - 1, -1, -1):
if(binary_numbers_list[digit] > 0):
answer += ((2 ** power) * binary_numbers_list[digit])
power += 1
return answer
```

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