Download Convert Binary Number in a Linked List to Integer.py
''' Given head which is a reference node to a singly-linked list. The value of each node in the linked list is either 0 or 1. The linked list holds the binary representation of a number. Return the decimal value of the number in the linked list. Example 1: Input: head = [1,0,1] Output: 5 Explanation: (101) in base 2 = (5) in base 10 Example 2: Input: head =  Output: 0 Example 3: Input: head =  Output: 1 Example 4: Input: head = [1,0,0,1,0,0,1,1,1,0,0,0,0,0,0] Output: 18880 Example 5: Input: head = [0,0] Output: 0 Constraints: The Linked List is not empty. Number of nodes will not exceed 30. Each node's value is either 0 or 1. ''' # Definition for singly-linked list. # class ListNode: # def __init__(self, x): # self.val = x # self.next = None class Solution: def getDecimalValue(self, head: ListNode) -> int: binary_numbers_list =  binary_numbers_list.append(head.val) while(head.next is not None): head = head.next binary_numbers_list.append(head.val) answer = 0 power = 0 # from len(binary_numbers_list) - 1 -> 0 for digit in range(len(binary_numbers_list) - 1, -1, -1): if(binary_numbers_list[digit] > 0): answer += ((2 ** power) * binary_numbers_list[digit]) power += 1 return answer
Leetcode 1290 Convert Binary Number in a Linked List to Integer problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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