# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def sumNumbers(self, root):
"""
:type root: TreeNode
:rtype: int
"""
if root is None:
return 0
res = 0
# bfs with queue
queue = [(root, root.val)]
while len(queue) > 0:
curr, curr_value = queue.pop(0)
if curr.left is None and curr.right is None:
res += curr_value
continue
if curr.left:
queue.append((curr.left, curr_value * 10 + curr.left.val))
if curr.right:
queue.append((curr.right, curr_value * 10 + curr.right.val))
return res
Download Sum Root to Leaf Numbers.pyLeetcode 129 Sum Root to Leaf Numbers problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
self.val = x
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