class Solution(object):
def solve(self, board):
# https://discuss.leetcode.com/topic/22503/some-tips-for-python-code
if not board:
return
height, width = len(board), len(board[0])
leakWall = self.buildLeakWall(board)
while leakWall:
i, j = leakWall.pop()
if 0 <= i < height and 0 <= j < width:
if board[i][j] == "O":
board[i][j] = "S"
leakWall += (i - 1, j), (i + 1, j), (i, j - 1), (i, j + 1)
for i in range(height):
for j in range(width):
board[i][j] = "O" if board[i][j] == "S" else "X"
def buildLeakWall(self, board):
leakWall, height, width = [], len(board), len(board[0])
for i in range(height):
if board[i][0] == "O":
leakWall.append((i, 0))
if board[i][width - 1] == "O":
leakWall.append((i, width - 1))
for j in range(width):
if board[0][j] == "O":
leakWall.append((0, j))
if board[height - 1][j] == "O":
leakWall.append((height - 1, j))
return leakWall
# def solve(self, board):
# # https://leetcode.com/problems/surrounded-regions/
# if not any(board): return
#
# height, width = len(board), len(board[0])
# save = [ij for k in range(height + width) for ij in ((0, k), (height - 1, k), (k, 0), (k, width - 1))]
# while save:
# i, j = save.pop()
# if 0 <= i < height and 0 <= j < width and board[i][j] == 'O':
# board[i][j] = 'S'
# save += (i, j - 1), (i, j + 1), (i - 1, j), (i + 1, j)
# board[:] = [['XO'[c == 'S'] for c in row] for row in board]
Download Surrounded Regions.pyLeetcode 130 Surrounded Regions problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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