Download Word Break.py
class Solution(object): def wordBreak(self, s, wordDict): """ :type s: str :type wordDict: Set[str] :rtype: bool """ queue =  ls = len(s) lenList = [l for l in set(map(len, wordDict))] visited = [0 for _ in range(0, ls + 1)] while queue: start = queue.pop(0) for l in lenList: if s[start:start + l] in wordDict: if start + l == ls: return True if visited[start + l] == 0: queue.append(start + l) visited[start + l] = 1 return False
Leetcode 139 Word Break problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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