class Solution(object):
def wordBreak(self, s, wordDict):
"""
:type s: str
:type wordDict: Set[str]
:rtype: bool
"""
queue = [0]
ls = len(s)
lenList = [l for l in set(map(len, wordDict))]
visited = [0 for _ in range(0, ls + 1)]
while queue:
start = queue.pop(0)
for l in lenList:
if s[start:start + l] in wordDict:
if start + l == ls:
return True
if visited[start + l] == 0:
queue.append(start + l)
visited[start + l] = 1
return False
Download Word Break.pyLeetcode 139 Word Break problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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