class Solution(object):
def reverseWords(self, s):
"""
:type s: a list of 1 length strings (List[str])
:rtype: nothing
"""
ls, pos = len(s), 0
if s is None or ls == 0:
return
self.reverse(s, 0, ls)
for i in range(ls + 1):
if i == ls or s[i] == ' ':
self.reverse(s, pos, i)
pos = i + 1
def reverse(self, array_s, begin, end):
for i in range((end - begin) / 2):
array_s[begin + i], array_s[end - i - 1] = array_s[end - i - 1], array_s[begin + i]
Download Reverse Words in a String II.pyLeetcode 186 Reverse Words in a String II problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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