# LeetCode 228Summary Ranges

## LeetCode 228 Summary Ranges Problem

``````class Solution(object):
# def summaryRanges(self, nums):
#     """
#     :type nums: List[int]
#     :rtype: List[str]
#     """
#     if nums is None or len(nums) == 0:
#         return []
#     res = []
#     start, prev, ls = nums[0], nums[0], len(nums)
#     for i in range(ls):
#         curr = nums[i]
#         if curr - prev > 1:
#             if start == prev:
#                 res.append("%d" % start)
#             else:
#                 res.append("%d->%d" % (start, prev))
#             start = curr
#         prev = curr
#     if start == prev:
#         res.append("%d" % start)
#     else:
#         res.append("%d->%d" % (start, prev))
#     return res

def summaryRanges(self, nums):
res = []
start, ls = 0, len(nums)
for i in range(ls):
if i + 1 <  ls and nums[i + 1] == nums[i] + 1:
continue
if i == start:
res.append(str(nums[start]))
else:
res.append("%d->%d" % (nums[start], nums[i]))
start = i + 1
return res
``````

## List of all Summary Ranges problems

Leetcode 228 Summary Ranges problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.

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