LeetCode 288 Unique Word Abbreviation

LeetCode 288 Unique Word Abbreviation Problem

Download Code
class ValidWordAbbr(object):
    def __init__(self, dictionary):
        initialize your data structure here.
        :type dictionary: List[str]
        self.dictionary = set(dictionary)
        self.abb_dic = {}
        for s in self.dictionary:
            curr = self.getAbb(s)
            if curr in self.abb_dic:
                self.abb_dic[curr] = False
                self.abb_dic[curr] = True

    def isUnique(self, word):
        check if a word is unique.
        :type word: str
        :rtype: bool
        abb = self.getAbb(word)
        hasAbbr = self.abb_dic.get(abb, None)
        return hasAbbr == None or (hasAbbr and word in self.dictionary)

    def getAbb(self, word):
        if len(word) <= 2:
            return word
        return word[0] + str(len(word) - 2) + word[-1]

        # Your ValidWordAbbr object will be instantiated and called as such:
        # vwa = ValidWordAbbr(dictionary)
        # vwa.isUnique("word")
        # vwa.isUnique("anotherWord")
Download Unique Word Abbreviation.py

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Leetcode 288 Unique Word Abbreviation problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.

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