class Solution(object):
# def minTotalDistance(self, grid):
# """
# :type grid: List[List[int]]
# :rtype: int
# """
# # sort
# rows = []
# cols = []
# for i in range(len(grid)):
# for j in range(len(grid[0])):
# if grid[i][j] == 1:
# rows.append(i)
# cols.append(j)
# row = rows[len(rows) / 2]
# cols.sort()
# col = cols[len(cols) / 2]
# return self.minDistance1D(rows, row) + self.minDistance1D(cols, col)
# def minDistance1D(self, points, origin):
# distance = 0
# for point in points:
# distance += abs(point - origin)
# return distance
def minDistance1D(self, points):
# two points
distance = 0
i, j = 0, len(points) - 1
while i < j:
distance += points[j] - points[i]
i += 1
j -= 1
return distance
def minTotalDistance(self, grid):
rows = self.collectRows(grid)
cols = self.collectCols(grid)
row = rows[len(rows) / 2]
col = cols[len(cols) / 2]
return self.minDistance1D(rows) + self.minDistance1D(cols)
def collectRows(self, grid):
rows = []
for i in range(len(grid)):
for j in range(len(grid[0])):
if grid[i][j] == 1:
rows.append(i)
return rows
def collectCols(self, grid):
cols = []
for j in range(len(grid[0])):
for i in range(len(grid)):
if grid[i][j] == 1:
cols.append(j)
return cols
Download Best Meeting Point.pyLeetcode 296 Best Meeting Point problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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