class Solution(object):
def numIslands2(self, m, n, positions):
"""
:type m: int
:type n: int
:type positions: List[List[int]]
:rtype: List[int]
"""
# quick union find with weights
ans = []
islands = Union()
for p in map(tuple, positions):
islands.add(p)
for dp in (0, 1), (0, -1), (1, 0), (-1, 0):
q = (p[0] + dp[0], p[1] + dp[1])
if q in islands.id:
islands.unite(p, q)
ans += [islands.count]
return ans
class Union(object):
"""
quick union find with weights
"""
def __init__(self):
# use dic to reduce index operations
self.id = {}
self.sz = {}
self.count = 0
def add(self, p):
self.id[p] = p
self.sz[p] = 1
self.count += 1
def root(self, i):
while i != self.id[i]:
self.id[i] = self.id[self.id[i]]
i = self.id[i]
return i
def unite(self, p, q):
i, j = self.root(p), self.root(q)
if i == j:
return
if self.sz[i] > self.sz[j]:
i, j = j, i
self.id[i] = j
self.sz[j] += self.sz[i]
self.count -= 1
Download Number of Islands II.pyLeetcode 305 Number of Islands II problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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