LeetCode 328 Odd Even Linked List

LeetCode 328 Odd Even Linked List Problem

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# Definition for singly-linked list.
# class ListNode(object):
#     def __init__(self, x):
#         self.val = x
#         self.next = None

class Solution(object):
    def oddEvenList(self, head):
        :type head: ListNode
        :rtype: ListNode
        odd = head
        if head is None:
            return None
        if head.next is None:
            return head
        even_head = even = head.next
        while odd.next is not None and even.next is not None:
            odd.next = even.next
            odd = odd.next
            even.next = odd.next
            even = even.next
        odd.next = even_head
        return head

    # def oddEvenList(self, head):
    #     # slicing
    #     if (head != None):
    #         x = []
    #     else:
    #         return []
    #     while (head.next != None):
    #         x.append(head.val)
    #         head = head.next
    #     x.append(head.val)
    #     return x[0::2] + x[1::2]
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Leetcode 328 Odd Even Linked List problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.

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