class Solution(object):
# def fizzBuzz(self, n):
# """
# :type n: int
# :rtype: List[str]
# """
# res = []
# for i in range(1, n + 1):
# if i % 3 == 0:
# if i % 5 == 0:
# res.append('FizzBuzz')
# else:
# res.append('Fizz')
# elif i % 5 == 0:
# res.append('Buzz')
# else:
# res.append(str(i))
# return res
# def fizzBuzz(self, n):
# """
# :type n: int
# :rtype: List[str]
# """
# res = []
# for i in range(1, n + 1):
# curr = ''
# if i % 3 == 0:
# curr += 'Fizz'
# if i % 5 == 0:
# curr += 'Buzz'
# if not len(curr):
# curr += str(i)
# res.append(curr)
# return res
def fizzBuzz(self, n):
return [str(i) * (i % 3 != 0 and i % 5 != 0) + "Fizz" * (i % 3 == 0) + "Buzz" * (i % 5 == 0)
for i in range(1, n + 1)]
# def fizzBuzz(self, n):
# return ['Fizz' * (not i % 3) + 'Buzz' * (not i % 5) or str(i) for i in range(1, n+1)]
Download Fizz Buzz.pyLeetcode 412 Fizz Buzz problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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