class Solution(object):
def validWordSquare(self, words):
"""
:type words: List[str]
:rtype: bool
"""
if words is None or len(words) == 0:
return True
ls = len(words)
for i in range(ls):
for j in range(1, len(words[i])):
if j >= ls:
return False
if i >= len(words[j]):
return False
if words[i][j] != words[j][i]:
return False
return True
# def validWordSquare(self, words):
# # https://discuss.leetcode.com/topic/63423/1-liner-python/2
# # The map(None, ...) transposes the "matrix", filling missing spots with None
# return map(None, *words) == map(None, *map(None, *words))
Download Valid Word Square.pyLeetcode 422 Valid Word Square problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
Feedback is the most important part of any website.
If you have any query, suggestion or feedback, Please feel free to contact us.