Download Valid Word Square.py
class Solution(object): def validWordSquare(self, words): """ :type words: List[str] :rtype: bool """ if words is None or len(words) == 0: return True ls = len(words) for i in range(ls): for j in range(1, len(words[i])): if j >= ls: return False if i >= len(words[j]): return False if words[i][j] != words[j][i]: return False return True # def validWordSquare(self, words): # # https://discuss.leetcode.com/topic/63423/1-liner-python/2 # # The map(None, ...) transposes the "matrix", filling missing spots with None # return map(None, *words) == map(None, *map(None, *words))
Leetcode 422 Valid Word Square problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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