class Solution(object):
# def letterCasePermutation(self, S):
# ans = [[]]
# for char in S:
# n = len(ans)
# if char.isalpha():
# # Double the ans
# for i in xrange(n):
# ans.append(ans[i][:])
# ans[i].append(char.lower())
# ans[n + i].append(char.upper())
# else:
# # Normal append
# for i in xrange(n):
# ans[i].append(char)
# return map("".join, ans)
def letterCasePermutation(self, S):
B = sum(letter.isalpha() for letter in S)
ans = []
for bits in xrange(1 << B):
b = 0
word = []
for letter in S:
if letter.isalpha():
if (bits >> b) & 1:
word.append(letter.lower())
else:
word.append(letter.upper())
b += 1
else:
word.append(letter)
ans.append("".join(word))
return ans
Download Letter Case Permutation.pyLeetcode 784 Letter Case Permutation problem solution in python3 with explanation. This is the best place to expand your knowledge and get prepared for your next interview.
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